将python转换为伪Cod

Question

作为一个初学者，我正在努力将这段代码转换成伪代码。有人能帮忙吗？我将非常感激。。。

for i in range (0,len(sentence_split)):
    found = False  
    for j in range (0,len(words)):
        if sentence_split[i] == words [j]:
            found=True
    if found==False:
        words.append(sentence_split[i])

Answer 1

如果您以pythonic的方式编写代码，它看起来像伪代码，并且仍将运行。

for part in sentence_split:
    if part not in words:
        words.append(part)