擅长:python、mysql、java
<p>我猜您可能想<code>re.sub</code>变量<code>word-spacing</code>:</p>
<pre><code>import re
regex = r"\s*word-spacing\s*:\s*[^;]*;"
test_str = '''
style="font-family: scala-sans-offc-pro ; width: 100%; word-spacing: -3.71429px;"
style="font-family: scala-sans-offc-pro ; width: 100%; word-spacing: -5px;"
style="font-family: scala-sans-offc-pro ; width: 100%;"
'''
print(re.sub(regex, "", test_str))
</code></pre>
<hr/>
<h3>输出</h3>
<pre><code>style="font-family: scala-sans-offc-pro ; width: 100%;"
style="font-family: scala-sans-offc-pro ; width: 100%;"
style="font-family: scala-sans-offc-pro ; width: 100%;"
</code></pre>
<hr/>
<blockquote>
<p>If you wish to explore/simplify/modify the expression, it's been
explained on the top right panel of
<a href="https://regex101.com/r/azzXIO/1/" rel="nofollow noreferrer">regex101.com</a>. If you'd like, you
can also watch in <a href="https://regex101.com/r/azzXIO/1/debugger" rel="nofollow noreferrer">this
link</a>, how it would match
against some sample inputs.</p>
</blockquote>
<hr/>