如何使用python有条件地存储一个值？

Question

所以基本原理是，我试图让一个用户输入他们的年薪，然后程序会运行一组if语句，然后返回他们所处的税级，从他们的年薪中减去金额，返回他们的总收入。主要的问题是，它将运行正确的金额为0-9525美元，但一旦你跳到12%和22%，它并没有使他们的。比如，如果你输入100000美元，它只会从中扣除12%，而它应该扣除24%。以下是当前形式的Python代码：

#Takes someone's yearly salary
yearlySalary = eval(input("Please enter your yearly salary: "))

if(yearlySalary < 9525):
    tax = yearlySalary * .10
    yearlySalary = yearlySalary-tax

elif(yearlySalary > 9526 && yearlySalary < 38700):
    tax = yearlySalary * .12
    yearlySalary = yearlySalary-tax

elif(range (38701, 82500)):
    tax = yearlySalary * .22
    yearlySalary = yearlySalary-tax

elif(range (82501, 157500)):
    tax = yearlySalary * .24
    yearlySalary = yearlySalary-tax

elif(range(157501, 200000)):
    tax = yearlySalary * .32
    yearlySalary = yearlySalary-tax

elif(range(200001, 500000)):
    tax = yearlySalary * .35
    yearlySalary = yearlySalary-tax

elif(yearlySalary > 500001):
    tax = yearlySalary * .37
    yearlySalary = yearlySalary-tax

Answer 1

这里有一些关于税级如何工作的问题；税级应该以相反的顺序排列，以便首先抓住最高的税级，并且只有超过税级的金额才应该按该金额征税。你知道吗

另外，在您的示例中，elif(range (82501, 157500)):不会捕获年薪=100000，因为else语句没有断言年薪是否在该范围内。你知道吗

由于使用了不正确的“AND”运算符，它被捕获在12%中：使用and而不是&&。你知道吗

Answer 2

使用^{}：

• 它允许更干净的代码
• yearlySalary是装箱的，没有混乱的代码，如：
  • yearlySalary > 9526 & yearlySalary < 38700
  • elif(yearlySalary in range (38701, 82500))
• 对于以下代码，箱子大小如下
  • 0-9525为10%
  • 9526-38700的12%
  • 38701-82500为22%
  • 82501-157500的24%
  • 157501-200000的32%
  • 200001-500000的35%
  • 500001及以上为37%
• .digitize的工作原理是找到bins的索引，其中income落在其中。给定索引，在tax_per中找到相应的值。你知道吗
• bin_用作变量，因为bin是一个内部python函数，我们不会覆盖内部函数。你知道吗

import numpy as np

def tax_bracket(income: float) -> float:
    tax_per = np.array([.10, .12, .22, .24, .32, .35, .37])
    bin_ = np.digitize(income, bins=[9526, 38701, 82501, 157501, 200001, 500001])
    return income - income*(tax_per[bin_])


yearlySalary = float(input("Please enter your yearly salary: "))
print(tax_bracket(yearlySalary))

输出：

Please enter your yearly salary:  37524
33021.12

使用if - elif - else：

• 从大到小排列箱子。你知道吗

def old_way(yearlySalary):

    if yearlySalary > 500000:
        tax = yearlySalary * .37
        yearlySalary = yearlySalary-tax

    elif yearlySalary > 200000:
        tax = yearlySalary * .35
        yearlySalary = yearlySalary-tax

    elif yearlySalary > 157500:
        tax = yearlySalary * .32
        yearlySalary = yearlySalary-tax

    elif yearlySalary > 82500:
        tax = yearlySalary * .24
        yearlySalary = yearlySalary-tax

    elif yearlySalary > 38700:
        tax = yearlySalary * .22
        yearlySalary = yearlySalary-tax

    elif yearlySalary > 9525:
        tax = yearlySalary * .12
        yearlySalary = yearlySalary-tax

    else:
        tax = yearlySalary * .10
        yearlySalary = yearlySalary-tax

    return yearlySalary

Answer 3

你必须改变你的elif，比如：

elif(yearlySalary in range (38701, 82500)):

想知道你的年薪是否在这个范围内