在python中查找所有linux文件的通用目录

Question

我想在python中找到所有linux文件的通用目录（不是目录）。大家能帮帮我吗？你知道吗

例1：

['/home/tung/abc.txt', '/home/tung/xyz.txt']
    -> general directory: '/home/tung'

例2：

['/home/tung/abc.txt', '/home/tung/xyz.txt', '/home/user/123.txt']
    -> general directory: '/home'

例3：

['/home/tung/abc.txt', '/root/xyz.txt']
    -> general directory: '/'

Answer 1

os.path.commonprefix(list)

Return the longest path prefix (taken character-by-character) that is a prefix of all paths in list. If list is empty, return the empty string (''). Note that this may return invalid paths because it works a character at a time.

---

或者，如果您使用的是Python3.4+（我想这部分答案更适合未来），您可以使用pathlib和： PurePaths.parts会给你一个

tuple giving access to the path’s various components.

将不同文件的元组转换为列表，然后找到common list of prefixes for a list of lists。你知道吗

Answer 2

这是我的密码：

def test(l):
l = [s.split('/') for s in l]
len_list = len(l)
min_len = min(len(s) for s in l)
i = 0
result = ''
while i < min_len:
    j = 1
    while j < len_list:
        if l[0][i] != l[j][i]:
            return result
        j += 1
    result = '%s%s/' % (result, l[0][i])
    i += 1
return result

Answer 3

已经在RosettaCode上完成了：http://rosettacode.org/wiki/Find_common_directory_path#Python