在python中,我尝试创建一个简单的游戏,玩家可以选择下一个要去的洞穴,同时尽量避开wumpus。在设置初始洞穴结构时,它会以某种方式停止,并且永远不会启动游戏,出现以下错误:
Traceback (most recent call last):
File "/Users/JPagz95/Documents/Hunt_the_Wumpus_3.py", line 80, in <module>
link_caves()
File "/Users/JPagz95/Documents/Hunt_the_Wumpus_3.py", line 28, in link_caves
this_cave = choose_cave(visited_caves)
File "/Users/JPagz95/Documents/Hunt_the_Wumpus_3.py", line 50, in choose_cave
cave_number = choice(cave_list)
File "/Users/JPagz95/anaconda/lib/python3.5/random.py", line 253, in choice
i = self._randbelow(len(seq))
KeyboardInterrupt
这是游戏的最新代码。感谢您的帮助:)
from random import choice
cave_numbers = [x for x in range(20)]
unvisited_caves = [x for x in range(20)]
visited_caves = []
def setup_caves(cave_numbers):
""" create a starting list of caves """
caves = []
for number in cave_numbers:
caves.append(number)
return caves
def visit_cave(cave_number):
""" mark a cave as visited """
visited_caves.append(cave_number)
unvisited_caves.remove(cave_number)
def print_caves():
""" print out the current cave structure """
for number in cave_numbers:
print (number, ":", caves[number])
print ('----------')
def link_caves():
""" make sure all of the caves are connected with two way tunnels"""
while unvisited_caves != []:
this_cave = choose_cave(visited_caves)
next_cave = choose_cave(unvisited_caves)
create_tunnel(this_cave, next_cave)
visit_cave(next_cave)
def create_tunnel(cave_from, cave_to):
""" create a tunnel between cave_from and cave_to """
caves[cave_from].append(cave_to)
caves[cave_to].append(cave_from)
def finish_caves():
""" link the rest of the caves with one way tunnels """
for caves in cave_numbers:
while len(caves) < 3:
passage_to = choose_cave(cave_numbers)
caves[cave].append(passage_to)
def choose_cave(cave_list):
""" pick a cave from a list, provided that the
cave has less than 3 tunnels """
cave_number = choice(cave_list)
while len(caves) >= 3:
cave_number = choice(cave_list)
return cave_number
def print_location(player_location):
""" tell the player about where they are """
print ("You are in a cave ", player_location)
print ("From here you can see caves: ")
print (caves[player_location])
if wumpus_location in caves[player_location]:
print ("I smell a wumpus!")
def get_next_location():
""" Get the player's next location """
print ("Which cave next?")
player_input = input(">")
if (not player_input.isdigit() or
int(player_input) not in
caves[player_location]):
print (player_input + "?")
print ("That's not a direction I can see!")
return none
else:
return int(player_input)
caves = setup_caves(cave_numbers)
visit_cave(0)
print_caves()
link_caves()
print_caves()
finish_caves()
wumpus_location = choice(cave_numbers)
player_location = choice(cave_numbers)
while player_location == wumpus_location:
player_location = choice(cave_numbers)
print ("Welcome to Hunt the Wumpus!")
print ("You can see ", len(cave_numbers), " caves")
print ("To play, just type the number")
print ("of the cave you wish to enter next")
while True:
print_location(player_location)
new_location = get_next_location()
if new_location != None:
player_location = new_location
if player_location == wumpus_location:
print ("Aargh! You got eaten by a wumpus!")
TigerhawkT3的详细回答。你知道吗
我最近研究了这段代码的一个版本,您可能只需稍加修改就可以解决一个问题。通过缩进最后两行使其位于“while”循环中,修复link\u caves()函数中的拼写错误:
该更改将创建所需的隧道,并在每次通过循环时调用visit\u cave()。 visit_cave()的最后一行从unvisted_caves列表中删除正确的洞穴,这是TigerhawkT3提到的必要条件。你知道吗
你确实有一些问题要解决,完成初始化并让游戏运行。你知道吗
回溯语句将告诉您从何处开始查找。你知道吗
您可以添加print语句来显示列表,以帮助您在代码挂起之前调试代码。你知道吗
如果您将洞的数量改为4-5而不是20,那么在调试时输出可能更容易查看。你知道吗
首先:
然后:
然后:
然后:
您正在向
random.choice()
发送一个空的list
,但失败了。你知道吗将
link_caves()
更改为仅处理非空的list
:注意,如果这个函数没有向
random.choice()
传递一个无效的参数,它就会陷入困境,因为它使用了一个while
循环,在这个循环中条件永远不会改变。我注意到您也在choose_cave()
中使用while len(caves) >= 3: cave_number = choice(cave_list)
执行此操作。这个特定的片段将检查caves
的长度,如果是>= 3
,则从cave_list
中随机选择一个洞穴。然后它将检查caves
的长度,发现它和以前一样,选择一个随机的洞穴,等等,直到永远。也许您希望random.choice()
从传递的序列中删除它所选的项。它不这样做。如果需要,可以通过多种方式删除它,例如在随机选取cave_number
之后执行caves.remove(cave_number)
。你知道吗请记住,除了提示您的问题和我指出的其他错误之外,您的代码中可能还有其他错误。你知道吗
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