如果代码中的条件工作不正常，则代码中的任务之一

Question

https://www.codecademy.com/en/courses/python-beginner-P5YtY/1/6?curriculum_id=4f89dab3d788890003000096

def plane_ride_cost(city):

  if city== "Tampa" or "tampa":
      return 220 
  elif city== "Charlotte" or "charlotte":
      return 183
  elif city== "Pittsburgh" or "pittsburgh":
      return 222
  elif city== "Los Angeles" or "los angeles":
      return 474

在这段代码中，当提交给codeacedemy时，它只返回220，这是第一个返回值，我猜除了它没有被选中之外？你知道吗

Answer 1

不能像那样同时对照两个不同的值来检查city的值。你知道吗

def plane_ride_cost(city):
  if city == "Tampa" or city == "tampa":
      return 220 
  elif city == "Charlotte" or city == "charlotte":
      return 183
  elif city == "Pittsburgh" or city == "pittsburgh":
      return 222
  elif city == "Los Angeles" or city == "los angeles":
      return 474

或者

def plane_ride_cost(city):
  if city in ["Tampa","tampa"]:
      return 220 
  elif city in ["Charlotte","charlotte"]:
      return 183
  elif city in ["Pittsburgh","pittsburgh"]:
      return 222
  elif city in ["Los Angeles","los angeles"]:
      return 474

Answer 2

你能做到的

if city == "Tampa" or city == "tampa":

或者

if city in ("Tampa", "tampa"):

字符串的另一个选项是使用lower方法（如果需要不区分大小写的comparison）

if city.lower() == "tampa":

Answer 3

您需要确保对照两个值检查city的值：

即

if city == "Tampa" or city == "tampa":
    # do stuff

否则，Python会将其解释为(city == "Tampa") or ("tampa")，后者的值总是True

或者，如果要检查列表中的多个条件，可以将值放入数组中：

tampa = ["Tampa", "tampa"]
if city in tampa:
    # do stuff