如何使Pyglet媒体队列继续播放?

2024-03-29 11:21:21 发布

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我的播放机中有多首歌曲正在加载和排队,但是播放机在第一首歌曲之后停止,我必须使用next_source()手动强制下一首歌曲,尽管从文档中我认为这应该是自动的。你知道吗

我运行的是python3.7.1和pyglet1.3.2,我浏览了文档并尝试了不同的数据排队方法。我已经研究了确保文件完全播放,虽然我不确定是否播放结束的第一首歌。你知道吗

chosenDirectory = ""
cSong = ""
cSongIndex = 0
player = pyglet.media.Player()
songList = []


def chooseDirectory():
    global chosenDirectory
    chosenDirectory = tk.filedialog.askdirectory(initialdir="/")
    lbl.configure(text=chosenDirectory)
    listBox.delete("0", "end")

    def listFiles(dir):
        global songList
        songList = []
        files = os.listdir(dir)
        for x, file in enumerate(files):
            filePath = chosenDirectory + "/" + file
            if not os.path.isdir(filePath):
                fileExt = file.split(".")[1]
                if fileExt == "mp3" or fileExt == "wav":
                    listBox.insert(x, file)
                    songList.append(filePath)

    listFiles(chosenDirectory)


class mediaControls:
    def curSelect(self, info):
        global cSong
        if listBox.curselection() != ():
            selected = listBox.get(listBox.curselection())
            if selected != cSong:
                cSong = selected
                cSongIndex = listBox.curselection()[0]
        self.playList()

    def playSong(self):
        if not player.playing:
            player.play()
        elif player.playing:
            player.pause()

    def playList(self):
        for song in songList:
            music = pyglet.media.load(song)
            print(music.duration)
            player.queue(music)
        self.playSong()

    def playNextSong(self):
        player.next_source()

    def playNewSong(self):
        global cSong
        global cSongIndex
        cSongIndex = cSongIndex + 1
        cSong = listBox.get(cSongIndex)
        self.playSong()

我的预期结果是,在进入下一首歌之前,它会循环播放所有歌曲,而不需要我的干预。你知道吗


Tags: selfifdefglobalfileplayerselectedfilepath
2条回答

所以我希望队列能够处理所有的事情,而没有意识到pyglet.app.run程序()命令实际上是将所有事件设置为运动的命令。如果不使用它(因为它是阻塞的),我就可以在\u eos()上继续调用下一个\u source()函数并得到相同的结果。你知道吗

我想谈谈global的使用,因为你似乎已经处理了它不能继续发挥的问题。通过使状态成为类的一部分,可以消除global的所有用法。当应用程序运行时,它会生成该类的一个实例,该实例在程序运行的整个期间都有效。考虑以下几点。你知道吗

它不工作,因为你没有包括整个脚本。listBox似乎丢失了,并且应该是实例成员。你知道吗

class mediaControls:
    def __init__(self):
        self.chosenDirectory = ""
        self.cSong = ""
        self.cSongIndex = 0
        self.player = pyglet.media.Player()
        self.songList = []

    def chooseDirectory(self):
        self.chosenDirectory = chosenDirectory = tk.filedialog.askdirectory(initialdir="/")
        lbl.configure(text=chosenDirectory)
        listBox.delete("0", "end")

        songList = []
        files = os.listdir(chosenDirectory)
        for x, file in enumerate(files):
            filePath = os.path.join(chosenDirectory, file)
            if not os.path.isdir(filePath):
                fileExt = file.split(".")[1]
                if fileExt == "mp3" or fileExt == "wav":
                    listBox.insert(x, file)
                    songList.append(filePath)
        self.songList = songList

    def curSelect(self, info):
        if listBox.curselection() != ():
            selected = listBox.get(listBox.curselection())
            if selected != self.cSong:
                self.cSong = selected
                self.cSongIndex = listBox.curselection()[0]
        self.playList()

    def playSong(self):
        if not self.player.playing:
            self.player.play()
        elif self.player.playing:
            self.player.pause()

    def playList(self):
        for song in self.songList:
            music = pyglet.media.load(song)
            print(music.duration)
            self.player.queue(music)
        self.playSong()

    def playNextSong(self):
        self.player.next_source()

    def playNewSong(self):
        self.cSongIndex = self.cSongIndex + 1
        self.cSong = listBox.get(self.cSongIndex)
        self.playSong()

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