正则表达式匹配字符串中可能的名称

Question

我想从字符串中匹配可能的名称。一个名字应该是2-4个单词，每个单词有3个或更多的字母，所有单词都大写。例如，给定以下字符串列表：

Her name is Emily.
I work for Surya Soft.
I sent an email for Ery Wulandari.
Welcome to the Link Building Partner program!

我想要一个返回：

None
Surya Soft
Ery Wulandari
Link Building Partner

目前我的代码是：

data = [
   'Her name is Emily.', 
   'I work for Surya Soft.', 
   'I sent an email for Ery Wulandari.', 
   'Welcome to the Link Building Partner program!'
]

for line in data:
    print re.findall('(?:[A-Z][a-z0-9]{2,}\s+[A-Z][a-z0-9]{2,})', line)

它对前三行有效，但在最后一行失败。你知道吗

Answer 1

非正则表达式解决方案：

from string import punctuation as punc
def solve(strs):
   words = [[]]
   for i,x in enumerate(strs.split()):
      x = x.strip(punc)
      if x[0].isupper() and len(x)>2:
         if words[-1] and words[-1][-1][0] == i-1:
            words[-1].append((i,x))
         else:
            words.append([(i,x)])

   names = [" ".join(y[1] for y in x) for x in words if 2 <= len(x) <= 4]
   return ", ".join(names) if names else None


data = [
   'Her name is Emily.', 
   'I work for Surya Soft.', 
   'I sent an email for Ery Wulandari.', 
   'Welcome to the Link Building Partner abc Fooo Foo program!'
]
for x in data:
   print solve(x)

输出：

None
Surya Soft
Ery Wulandari
Link Building Partner, Fooo Foo

Answer 2

您可以使用：

re.findall(r'((?:[A-Z]\w{2,}\s*){2,4})', line)

它可以添加可以用.strip()修剪的尾随空格

Answer 3

您可以对重复结构使用分组，如下所示：

compiled = re.compile('(?:(([A-Z][a-z0-9]{2,})\s*){2,})')
for line in data:
    match = compiled.search(line)
    if match:
       print match.group()
    else:
       print None

输出：

None
Surya Soft
Ery Wulandari
Link Building Partner