如何在html中搜索链接并使用python打印链接？

Question

我正在尝试用python编写一个代码，它将在html代码中搜索图像链接，我需要找到的代码是- . 我需要找到http://www.darlighting.co.uk/621-large_default/empire-double-wall-bracket-polished-chrome.jpg部分，不管链接实际上说了什么，是否有其他方法可以这样做，或者我应该研究其他方法？我可以访问标准的python模块和beautifulsoup。你知道吗

Answer 1

import httplib
from lxml import html

#CONNECTION
url = "www.darlighting.co.uk"
path = "/"
conn = httplib.HTTPConnection(url)
conn.putrequest("GET", path)
#HERE YOU HEADERS... 
header = {"User-Agent": "Mozilla/5.0 (X11; Linux x86_64)", "Cache-Control": "no-cache"}
for k, v in header.iteritems():
    conn.putheader(k, v)
conn.endheaders()
res = conn.getresponse()

if res.status == 200:
    source = res.read()
else:
    print res.status
    print res.getheaders()

#EXTRACT
dochtml = html.fromstring(source)
for elem, att, link, pos in dochtml.iterlinks():
    if att == 'src': #or 'href'
        print 'elem: {0} || pos {1}: || attr: {2} || link: {3}'.format(elem, pos, att, link)