使用python对fasta序列的顺序进行排序

2024-09-30 00:37:33 发布

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我有一个fasta文件(由>;头行和序列行组成),如下所示:

米法斯塔

>S.sclerotiorum_Ch16_153_209
AACCCTAACCCTAACCCTTGATTGATTGATTGATTGATTGAT
TGATTGATGAAATTATAGTCTCCGTAAAGCAAATAAAGCATT
TAGTAAACGTTGAAGAGCTAGAAAAGCTTTAATACAAAAAGG
>S.sclerotiorum_Ch16_153_209
AACCCTAACCCTAACCCTTGATTGATTGATTGATTGATTGAT
TAGTAAACGTTGAAGAGCTAGAAAAGCTTTAATACAAAAAGG
>S.sclerotiorum_Ch14_442_1137
TGTCAATTCGATCTAGTATT
>S.sclerotiorum_Ch12_1831_180
AGAGCTAGAAAAGCTTTAAT
>S.sclerotiorum_Ch1_1831_180
AGAGCTAGAAAAGCTTTAATAGAGCTAGAAAAGCTTTAAT
AGAGCTAGAAAAGCTTTAATAGAGCTAGAAAAGCTTTAAT

我想按定义的顺序(从Ch1到Ch16)打印这个文件,得到如下结果:

>S.sclerotiorum_Ch1_1831_180
AGAGCTAGAAAAGCTTTAATAGAGCTAGAAAAGCTTTAAT
AGAGCTAGAAAAGCTTTAATAGAGCTAGAAAAGCTTTAAT
>S.sclerotiorum_Ch12_1831_180
AGAGCTAGAAAAGCTTTAAT
>S.sclerotiorum_Ch14_442_1137
TGTCAATTCGATCTAGTATT
>S.sclerotiorum_Ch16_153_209
AACCCTAACCCTAACCCTTGATTGATTGATTGATTGATTGAT
TAGTAAACGTTGAAGAGCTAGAAAAGCTTTAATACAAAAAGG
>S.sclerotiorum_Ch16_153_209
AACCCTAACCCTAACCCTTGATTGATTGATTGATTGATTGAT
TGATTGATGAAATTATAGTCTCCGTAAAGCAAATAAAGCATT
TAGTAAACGTTGAAGAGCTAGAAAAGCTTTAATACAAAAAGG

我试着写这段代码,但仍然得到与我的result.fasta中的输入文件相同的顺序。任何帮助将在修复我的代码。谢谢!你知道吗

代码:python代码.py我的法斯塔。法斯塔>;gt;结果.fasta你知道吗

#!/usr/bin/env python
import sys
import os
import pathlib

myfasta = sys.argv[1]
fasta = open(myfasta)

#types = ['S.sclerotiorum_Ch16_', 'S.sclerotiorum_Ch15_', 'S.sclerotiorum_Ch14_', 'S.sclerotiorum_Ch13_', 'S.sclerotiorum_Ch12_', 'S.sclerotiorum_Ch11_', 'S.sclerotiorum_Ch10_', 'S.sclerotiorum_Ch9_', 'S.sclerotiorum_Ch8_', 'S.sclerotiorum_Ch7_', 'S.sclerotiorum_Ch6_', 'S.sclerotiorum_Ch5_', 'S.sclerotiorum_Ch4_', 'S.sclerotiorum_Ch3_', 'S.sclerotiorum_Ch2_', 'S.sclerotiorum_Ch1_']

types = ['S.sclerotiorum_Ch1', 'S.sclerotiorum_Ch2', 'S.sclerotiorum_Ch3', 'S.sclerotiorum_Ch4', 'S.sclerotiorum_Ch5', 'S.sclerotiorum_Ch6', 'S.sclerotiorum_Ch7', 'S.sclerotiorum_Ch8', 'S.sclerotiorum_Ch9', 'S.sclerotiorum_Ch10', 'S.sclerotiorum_Ch11', 'S.sclerotiorum_Ch12', 'S.sclerotiorum_Ch13', 'S.sclerotiorum_Ch14', 'S.sclerotiorum_Ch15', 'S.sclerotiorum_Ch16']




for type in range(len(types)):
    flag = False
    fasta = open(myfasta)
    for line in fasta:
        if line.startswith('>') and types[type] in line:
            flag = True
        elif line.startswith('>'):
          flag = False
        if flag:
            #grabbed = line.strip()
            #newfasta.writelines(grabbed + "\n")
            print(line.strip())

fasta.close

Tags: 文件代码gtlinefastatypesflagch1
1条回答
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1楼 · 发布于 2024-09-30 00:37:33

您可以使用re.findall模式来匹配一行,然后是以非>字符开头的行,还可以将数字分组在Ch之后,使用sorted根据数字对匹配项进行排序,并使用str.join将排序后的子字符串连接回字符串:

import re
''.join(s for s, _ in sorted(re.findall(r'(.*_Ch(\d+)_.*\n(?:[^>].*\n)*)', f), key=lambda t: int(t[1])))

给定存储在f中的输入字符串(应首先将整个文件读入该变量),返回:

>S.sclerotiorum_Ch1_1831_180
AGAGCTAGAAAAGCTTTAATAGAGCTAGAAAAGCTTTAAT
>S.sclerotiorum_Ch12_1831_180
AGAGCTAGAAAAGCTTTAAT
>S.sclerotiorum_Ch14_442_1137
TGTCAATTCGATCTAGTATT
>S.sclerotiorum_Ch16_153_209
AACCCTAACCCTAACCCTTGATTGATTGATTGATTGATTGAT
TGATTGATGAAATTATAGTCTCCGTAAAGCAAATAAAGCATT
TAGTAAACGTTGAAGAGCTAGAAAAGCTTTAATACAAAAAGG
>S.sclerotiorum_Ch16_153_209
AACCCTAACCCTAACCCTTGATTGATTGATTGATTGATTGAT
TAGTAAACGTTGAAGAGCTAGAAAAGCTTTAATACAAAAAGG

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