擅长:python、mysql、java
<p>如果希望继续只依赖Pandas(即使它构建在Numpy之上),那么使用.loc索引器的正确语法是:</p>
<p><code>df.loc[row_indexer,column_indexer]</code></p>
<p>每只熊猫<a href="https://pandas.pydata.org/pandas-docs/version/0.17.0/indexing.html" rel="nofollow noreferrer">documentation</a>:</p>
<blockquote>
<p>This is the correct access method</p>
<p>In [305]: dfc = pd.DataFrame({'A':['aaa','bbb','ccc'],'B':[1,2,3]})</p>
<p>In [306]: dfc.loc[0,'A'] = 11</p>
</blockquote>
<p>。。。你知道吗</p>
<blockquote>
<p>This will not work at all, and so should be avoided</p>
<p>dfc.loc[0]['A'] = 1111</p>
</blockquote>