用Python打牌？

Question

我正在做一个程序，处理卡和分配5张随机卡给每个球员，直到我试图打印每个球员的手（摊牌功能）。我试图打印出给定玩家拥有的牌，但它告诉我“牌”不是全局属性。我知道不是，但我不知道如何为玩家打印卡片。帮忙？

import random

NUMCARDS = 52
DECK = 0
PLAYER = 1
COMP = 2

cardLoc = [0] * NUMCARDS
suitName = ("hearts", "diamonds", "spades", "clubs")
rankName = ("Ace", "Two", "Three", "Four", "Five", "Six", "Seven",
            "Eight", "Nine", "Ten", "Jack", "Queen", "King")
playerName = ("deck", "player", "computer")


#assigns random card to given player
def assignCard(str):

    #generates random card number to assign to player
    randomNum = random.randrange(0, NUMCARDS-1)

    #makes sure card being picked for player is not already assigned to another player
    while cardLoc[randomNum] != 0:
        randomNum = random.randrange(0, NUMCARDS-1)

    cardLoc[randomNum] = str


#shows all the cards in the deck
def showDeck():
    print "#      Card       Location"
    print "---------------------------"

    cardNum = 0

    for x in rankName:
        #assigns all ranks
        rank = x

        for y in suitName:
            #assigns all suits
            suit = y

            cards = "%s of %s" % (rank, suit)
            cardNum += 1

            location = cardLoc[cardNum-1]
            location = detLocation(location)

            print "%s  %s %s" % (cardNum, cards, location)
            global cards


#has program print out appropriate location instead of number
def detLocation(location):
    if location == PLAYER:
        return "Player"
    elif location == COMP:
        return "Computer"
    else:
        return "Deck"


#shows given player's hand... but not their foot (;
def showHand(str):
    global cards
    location = detLocation(str)
    print "Displaying %s Hand:" %location

    for i in range(5):
        cardLoc[cards] = str
        print "%s" % cardNum


#calls all functions necessary
def main():
    clearDeck()

    for i in range(5):
        assignCard(PLAYER)
        assignCard(COMP)

    #showDeck()
    showHand(PLAYER)
    showHand(COMP)

Answer 1

这可能无助于解决您的特定问题，但在继续使用Python时，它可能会给您一些想法。

import random

def main():
    suits = 'S H D C'.split()
    ranks = '2 3 4 5 6 7 8 9 X J Q K A'.split()
    deck  = [r + s for s in suits for r in ranks]
    n_players = 4
    hand_size = 5

    random.shuffle(deck)
    hands = deal(deck, n_players, hand_size)

    for h in hands:
        print h

def deal(deck, n_players, hand_size):
    # A general-purpose dealing function.
    # It takes a deck and returns a list of hands.
    # Each hand is a list of cards dealt from the top of the deck.
    hands = [[] for _ in range(n_players)]
    i = -1
    for _ in range(hand_size):
        for h in hands:
            i += 1
            h.append(deck[i])
    return hands

main()

关于该示例的一些一般要点：

• 这个例子不是从列表中随机选择项目（然后担心后续的选择是否与先前的选择重复），而是简单地洗牌，然后从顶部进行处理。

• 处理函数不依赖于任何全局变量。相反，它接收deck和其他参数作为参数，然后返回所需的指针。在某种程度上，您可以组织您的程序，以尽量减少（和本地化）对全局变量的依赖，您通常会更好（有许多原因）。

• 该示例使用列表理解，这是一种在Python中创建列表的便捷技术（其中初始化了deck和hands）。

Answer 2

我认为您需要一个全局卡对象，它被初始化并包含标签。类似于您在showDeck中所做的操作。它可能只是一个NUMCARDS数组。然后在showHand中遍历cardLoc并只打印给用户的：

for i in NUMCARDS:
    if cardLoc[i] == str:
        print cards[i]

我只是不确定您的对象层次结构是否适合这种情况，但我只是试图解决您的问题，而不是大量修改您的代码。

Answer 3

首先，您的assignCard函数不会修改全局变量（我假设这是您实际上不会做的事情） 所以你必须在那里加一行像global cardLoc 修改了这个全局变量后，您可以用以下代码打印卡片

for i in range(NUMCARDS-1):
    if cardLoc[i] == str:

打印指定给牌组中i位置的任何牌。