在python中，如何将列表中的独立项拆分为元组？

Question

好的，我有一个文件，里面有一些车的名字，以及它们的年限，像这样排列，但每一辆都是一条新的线：

Ford Focus - 5
Ford Focus - 7
Ford Focus - 3
VW Golf - 2
VW Golf - 6
VW Golf - 1

我试图找到一种方法来对这个进行元组化，但是细节是这样分开的：

[(Ford Focus - 5), (Ford Focus - 7), (Ford Focus - 3), (VW Golf - 2), (VW Golf - 6), (VW Golf - 1)]

谢谢

Answer 1

列表理解

data = [(line.strip(),) for line in open('file', 'r')]

for循环

data = []
for line in open('file', 'r') # for every line in file
    lst.append( (line.strip(),) ) # strip the line, make it to a tuple and append to lst

Answer 2

我相信，你真正想要的是一个(brand, year)形式的元组列表。如果是这样，那么

def parse_car_file(file_path):
    with open(file_path) as car_file:
        return [line.rstrip().split(" - ") for line in car_file]

否则

def parse_car_file(file_path):
    with open(file_path) as car_file:
        return [(line.rstrip(),) for line in car_file]