擅长:python、mysql、java
<p><strong>编辑</p>
<p>首先你的问题很难理解。但据我所知,你需要遍历文件夹和子文件夹,你可以用</p>
<pre><code>for root, dirs, files in os.walk(source): #Give your path in source
for file in filenames:
if file.endswith((".xlxs")): # You can check for any file extension
filename = os.path.join(subdir,file)
dirname = subdir.split(os.path.sep)[-1] # gets the directory name
print(dirname)
</code></pre>