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<p>我有以下清单:</p>
<pre><code>a = [[1,2,3,4,5], [4,5,6,7,8], [1,2,3,4], [4,5,6,7,8,9], [2,3,4,5,6,7,8], [6,7,8,9], [5,6,7,8,9], [2,3,4,5,6], [3,4,5,6], [11,12,13,14,15], [13,14,15]]
</code></pre>
<p>为便于理解,用索引表示:</p>
<pre><code>0 [1, 2, 3, 4, 5]
1 [4, 5, 6, 7, 8]
2 [1, 2, 3, 4]
3 [4, 5, 6, 7, 8, 9]
4 [2, 3, 4, 5, 6, 7, 8]
5 [6, 7, 8, 9]
6 [5, 6, 7, 8, 9]
7 [2, 3, 4, 5, 6]
8 [3, 4, 5, 6]
9 [11, 12, 13, 14, 15]
10 [13, 14, 15]
</code></pre>
<p>我希望输出是一个元组列表,如下所示:</p>
<pre><code>output = [(0,2,1), (3,1,1), (4,7,2), (4,1,2), (6,5,1), (3,5,2), (3,6,1), (7,8,1), (9,10,2)]
For example to explain first item of output i.e, (0,2,1):
0 ---> index of list under comparison with highest length
2 ---> index of list under comparison with lowest length
1 ---> difference in length of the two lists 0 & 2
</code></pre>
<p>现在,说到问题:</p>
<p>我有一些清单,清单的开头或结尾有一个和两个(或三个)长度不同的相似项目。你知道吗</p>
<p>我想排序,分组,识别列表的索引和它们作为元组的差异。你知道吗</p>
<p>我浏览了多个stackoverflow问题,但找不到类似的问题。你知道吗</p>
<p>我是python新手,从以下位代码开始,遇到了问题:</p>
<pre><code>a = sorted(a, key = len)
incr = [list(g) for k, g in groupby(a, key=len)]
decr = list(reversed(incr))
ndecr = [i for j in decr for i in j]
for i in range(len(ndecr)-1):
if len(ndecr[i]) - len(ndecr[i+1]) == 1:
print(ndecr[i])
for i in range(len(ndecr)-2):
if len(ndecr[i]) - len(ndecr[i+2]) == 2:
print(ndecr[i])
for i in ndecr:
ele = i
ndecr.remove(i)
for j in ndecr:
if ele[:-1] == j:
print(j)
for i in ndecr:
ele = i
ndecr.remove(i)
for j in ndecr:
if ele[:-2] == j:
print(i)
</code></pre>
<p>请帮助我采取什么方法来取得成果。你知道吗</p>