擅长:python、mysql、java
<p>您可以通过一个基本循环和一些条件来实现这一点:</p>
<pre><code>def check_places(L1, L2, places):
for i in places:
if i >= len(L1) or i >= len(L2) or L1[i] != L2[i]:
return False
return True
</code></pre>
<p>其工作原理如下:</p>
<pre><code>>>> L1 = ['X00013', 9654123, 4.1, 'No', 'No', 1.83, 3.8, 0.01, 90.01]
>>> L2 = ['X00014', 2021230, 1.23, 'Yes', 'No', 1.86, 3.65, 0.15, 0.00001]
>>> places = (3, 4, 7)
>>> check_places(L1, L2, places)
False
</code></pre>