zip中的键和值

2024-09-27 17:32:37 发布

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注意:我是Python新手。你知道吗

我的任务是设计一个程序,可以输出外国的车牌号,但是如果他们超速的话只能输出。我可能在这一过程中犯了一些错误,但我需要帮助列出计时2和字典计时3。 #UK#F只是我的笔记,以便我能够快速查看哪个是英国牌照,哪个是外国牌照。你知道吗

import re

distance=750 #variable for the distance between the Camera A and B (in m)
speedlimit=70 # (mps)
NumberPlates=["DV61 GGB",#UK
              "DS11 EUBG 20",#F
              "5T314 10A02",#F
              "24TEG 5063",#F
              "TR09 TRE",#UK
              "524 WAL 75",#F
              "TR44 VCZ",#UK
              "FR52 SWD",#UK
              "100 GBS 12",#F
              "HG55 BPO"#UK
              ]

Enter=[7.12,7.15,7.24,7.45,7.28,7.31,7.18,7.25,7.33,7.38] #A list for the times of cars passing Camera A

Leave=[7.56,7.24,7.48,7.52,7.45,7.57,7.22,7.31,7.37,7.47] #A list for the times of cars passing Camera B

Timestaken=[]
Timestaken2=[]
Timestaken3={}

for enter_data, leave_data in zip(Enter, Leave):
    Timestaken.append(leave_data-enter_data)

Timestaken=["%.2f" % (leave_data-enter_data) for enter_data, leave_data in zip(Enter, Leave)]
Timestaken2=[s.strip("0") for s in Timestaken]
Timestaken2=[s.strip('.') for s in Timestaken2]

for key,value in zip(NumberPlates,Timestaken2):
    Timestaken3[key]=value

print(Timestaken3)

for item in NumberPlates:
    UK_Numbers=list(filter(lambda x: re.match("[A-Z]{2}\d{2}\s+[A-Z]{3}$",x),NumberPlates))
    for item in UK_Numbers:
        if item in UK_Numbers:
            NumberPlates.remove(item)

print(NumberPlates)

for key,value in zip(NumberPlates,Timestaken2):
    Timestaken3[key]=value

print(Timestaken3)

print("10 cars have passed Camera A, then Camera B\n")

for key,value in Timestaken3.items():
    speed=distance/int(value)
    if speed>speedlimit:
        print(key,"is speeding with",speed,"mps")

我在程序中加入了print(),以查看程序最终执行的操作。第二次是:

for key,value in zip(NumberPlates,Timestaken2):
    Timestaken3[key]=value

我只希望剩下的数字板,这将是外国的打印后,这个代码的权利。Timestaken2仍然有10个值,这是问题吗?你知道吗

请帮我解决任何问题。你知道吗


Tags: thekeyinfordatavaluezipcamera
2条回答

问题是您正在代码的第二部分重用TimesTaken3。如果您为超速行驶的外国汽车创建了一个新词典TimestakenForeign,那么您的代码似乎可以正常工作:

print(NumberPlates)    

TimestakenForeign = {}

for key,value in zip(NumberPlates,Timestaken2):
    TimestakenForeign[key]=value

print(TimestakenForeign)

print("10 cars have passed Camera A, then Camera B\n")

for key,value in TimestakenForeign.items():
    speed=distance/int(value)
    if speed>speedlimit:
        print(key,"is speeding with",speed,"mps")

不太确定,但也许你只是想编一本新字典:

Timestaken4={}

for key,value in zip(NumberPlates,Timestaken2):
    Timestaken4[key]=value

print(Timestaken4)

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