如何更改此函数调用和算法以在大小为n的列表中找到值最小的字符串。不使用min函数

Question

如何更改此函数调用和算法以在大小为n的列表中找到值最小的字符串。此外，我还了解内置的min函数，我只是试图理解其机制。让我先说我是第一学期的学生，所以我为我的无知提前道歉。你知道吗

def main():


    strOne = 'stack'
    strTwo = 'over'
    strThree = 'flow'
    strFour = 'please'
    strFive = 'help'

    first = alphabetical(strOne, strTwo, strThree, strFour, strFive)

    print(first)

def alphabetical(one, two, three, four, five):
    low = one
    if two < low:
        low = two
    if three < low:
        low = three
    if four < low:
        low = four
    if five < low:
        low = five  
    return low

main()

    ###################################################################      
    # str_list = ['stack', 'over', 'flow', 'please', 'help'] ??       #
    # for i in str_list: ?? perhaps on the right track with this idea.#
    #       first = alphabetical(i) ?? maybe                          #  
    ###################################################################

Answer 1

您可以使用内置函数min:

>>> min('stack', 'over', 'flow', 'please', 'help')
   'flow'