在python、c++中解析给定特定形式的文本文件

Question

我有一个以下格式的文件；我想用pyhton和c++解析它，并提取ImpVarNo后面的数字： 这种格式有很多行。你知道吗

你知道吗示例.txt你知道吗

Start:
abc pqr
(FF_GGGGG_CONFIRM_TR):TC:20222,SeqNum:86,ImpVarNo:1000000008234436,Id:12,oneId:66454,a/c:1,ImpValue:905,Impvar:25,actualValue:905,actualVar:25,abc pqr xyz
Impquantity:0,pgb ncr yepp
Start:
abc pqr
(FF_GGGGG_CONFIRM_TR):TC:20222,SeqNum:86,ImpVarNo:1000000008234436,Id:12,oneId:66454,a/c:1,ImpValue:905,Impvar:25,actualValue:905,actualVar:25,abc pqr xyz
Impquantity:0,pgb ncr yepp
Start:
abc pqr
(FF_GGGGG_CONFIRM_TR):TC:20222,SeqNum:86,ImpVarNo:1000000008234436,Id:12,oneId:66454,a/c:1,ImpValue:905,Impvar:25,actualValue:905,actualVar:25,abc pqr xyz
Impquantity:0,pgb ncr yepp
Start:
abc pqr
(FF_GGGGG_CONFIRM_TR):TC:20222,SeqNum:86,ImpVarNo:1000000008234436,Id:12,oneId:66454,a/c:1,ImpValue:905,Impvar:25,actualValue:905,actualVar:25,abc pqr xyz
Impquantity:0,pgb ncr yepp

所以我写了以下代码：

#!/usr/bin/env python

import sys
import re

hand = open('newlogfile.txt')
for line in hand:
    r = re.compile("ExOrderNo:(\d+),") 
    print r 

Answer 1

import re
with  open('newlogfile.txt') as f:
    r = re.compile("ImpVarNo:(\d+),")
    for line in f:
        inp = r.findall(line)
        if inp:
            print(float(inp[0]))

1000000008234436
1000000008234436
1000000008234436
1000000008234436

如果行总是以相同的东西开头：

   import re
    with  open('newlogfile.txt') as f:
        r = re.compile("ImpVarNo:(\d+),")
        for line in f:
            if line.startswith("(FF_GGGGG_CONFIRM_TR)"):
                print(r.findall(line))

Answer 2

不过，这是最简单的方法，您可以使用RegEx使代码更干净。你知道吗

sample_file = open(sample.txt)
contents = sample_file.readlines()
for line in contents:
    if line.startswith("(FF_GGGGG_CONFIRM_TR)"):
        number_after_impvarno = int(line.split(",")[2][9:])