擅长:python、mysql、java
<p>因为<a href="https://docs.python.org/2/library/re.html#re.findall" rel="nofollow">re.findall</a>返回项目列表</strong>,所以在匹配的项目<code>[]</code>周围得到^{<strong></p>
<pre><code>link = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+', link)
# pay attention on iteration over set(links) and not links
for link in set(links):
print link
</code></pre>
<p>请注意,我已经将<a href="https://docs.python.org/2/library/stdtypes.html#set" rel="nofollow">^{<cd2>}</a>创建添加到<code>for loop</code>中,以仅获取唯一链接,这样您就可以防止打印相同的url。你知道吗</p>