我在使用python3amazonapi时遇到了一个问题。我注意到很多人都有同样的问题,但我到处寻找解决办法却没有结果。你知道吗
我在尝试这段简单的代码:
from amazon.api import AmazonAPI
amazon = AmazonAPI (my_AMAZON_ACCESS_KEY, my_AMAZON_SECRET_KEY, my_AMAZON_ASSOC_TAG, region=’IT’)
products = amazon.search(Keywords = "book name", SearchIndex = "Books")
print(products)
#<amazon.api.AmazonSearch object at 0x7fcc238e7a20>
在这之前它是有效的。你知道吗
for item in products:
print (item.title, item.isbn, item.price_and_currency)
这里我得到以下错误:
File "amazon_loader.py", line 78, in getItemFromAmazon
for item in products:
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/site-packages/amazon/api.py", line 544, in __iter__
for page in self.iterate_pages():
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/site-packages/amazon/api.py", line 561, in iterate_pages
yield self._query(ItemPage=self.current_page, **self.kwargs)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/site-packages/amazon/api.py", line 573, in _query
response = self.api.ItemSearch(ResponseGroup=ResponseGroup, **kwargs)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/site-packages/bottlenose/api.py", line 274, in __call__
{'api_url': api_url, 'cache_url': cache_url})
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/site-packages/bottlenose/api.py", line 235, in _call_api
return urllib2.urlopen(api_request, timeout=self.Timeout)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 223, in urlopen
return opener.open(url, data, timeout)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 532, in open
response = meth(req, response)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 642, in http_response
'http', request, response, code, msg, hdrs)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 570, in error
return self._call_chain(*args)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 504, in _call_chain
result = func(*args)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 650, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 403: Forbidden
我想这是python库的问题,而不是AmazonAPI的问题。此外,我假设在尝试从下载的AmazonSearch对象请求信息时与标识有关,但我不知道如何解决该问题。你知道吗
我也试过Python2,没有区别。你知道吗
目前没有回答
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