印刷线条在Python中表现得很奇怪

Question

我想在几个循环中打印一堆行，我想找到一种不使用\n打印行的方法，因为这样在每个循环完成后都会添加一个空行。我的代码示例如下：

def compose_line6(self, pointers, pointers_synset_type):    
    self.line6 = ''
    for A, B in zip(pointers, pointers_synset_type):
        self.line6 += 'http://www.example.org/lexicon#'+A+' http://www.monnetproject.eu/lemon#pos '+B+'\n'
    return self.line6

def compose_line7(self, pointers, pointer_source_target):
    self.line7 = ''
    for A, B in zip(pointers, pointer_source_target):
        self.line7 += 'http://www.example.org/lexicon#'+A+' http://www.monnetproject.eu/lemon#source_target '+B+'\n'
    return self.line7

def compose_contents(self, line1, line2, line3, line4, line5, line6, line7):
    self.contents = '''\
    '''+line1+'''
    '''+line2+'''
    '''+line3+'''
    '''+line4+'''
    '''+line5+'''
    '''+line6+'''
    '''+line7+''''''
    return self.contents

def print_lines(self, contents):
    print (contents)

当我打印这些时，会发生这样的情况：

        http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#pos n
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#pos a
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#pos v

        http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#source_target 0000
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#source_target 0401
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#source_target 0302
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#source_target 0203
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#source_target 0101

我想要这样：

http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#pos n
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#pos a
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#pos v
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#pos v    
http://www.example.org/lexicon#13796604 http://www.monnetproject.eu/lemon#source_target 0000
http://www.example.org/lexicon#00603894 http://www.monnetproject.eu/lemon#source_target 0401
http://www.example.org/lexicon#00753137 http://www.monnetproject.eu/lemon#source_target 0302
http://www.example.org/lexicon#01527311 http://www.monnetproject.eu/lemon#source_target 0203
http://www.example.org/lexicon#02361703 http://www.monnetproject.eu/lemon#source_target 0101

帮帮忙太好了谢谢

Answer 1

在Python2.x中，逗号后面是print "Text",-nothing。你知道吗

在python3.x中，它将是print("Text", end="")—只是print()函数的特殊参数。你知道吗

Answer 2

在添加换行符之前，您需要关闭报价：

'''\
    '''+line1+'''
    '''+line2+'''
    '''+line3+'''
    '''+line4+'''
    '''+line5+'''
    '''+line6+'''
    '''+line7+''''''

您跳过了第一个换行符，但它仍然在line1后面添加了4个空格。试试这个：

print("\n".join([line1, line2, line3, line4, line5, line 6, line7]))

Answer 3

用途：

def compose_contents(self, line1, line2, line3, line4, line5, line6, line7):
    self.contents = '\n'.join([line1, line2, line3, line4, line5, line6, line7])
    return self.contents

以及：

print contents,

注意结尾的逗号！你知道吗