擅长:python、mysql、java
<p>你可以这样做:</p>
<pre><code>def in_list(list_of_lists, item):
for list_ in list_of_lists:
if item in list_:
return list_
</code></pre>
<p>编辑:</p>
<p>下面是它的递归版本:</p>
<pre><code>def in_list(list_of_lists, item):
if not list_of_lists:
return None
if item in list_of_lists[0]:
return list_of_lists[0]
return in_list(list_of_lists[1:], item)
</code></pre>