<p>不知道你的方法需要多灵活。我假设您在OrderedDict中有一些公共键,您希望在那里找到度量,然后将它们重新格式化为新的dict。你知道吗</p>
<pre><code>from collections import OrderedDict
import json
def reformat_ordered_dict(dict_result):
"""Reconstruct the OrderedDict result into specific format
This method assumes that your input OrderedDict has the following common keys: 'index',
'host', 'source', '_time', and a potential metric whcih is subject to change (of course
you can support more metrics with minor tweak of the code). The function also re-map the
keys (for example, mapping '_time' to 'times', pack 'index' and 'source' into 'servarname'
).
:param dict_result: the OrderedDict
:return: the reformated OrderedDict
"""
common_keys = ('index', 'host', 'source', '_time')
assert all(common_key in dict_result for common_key in common_keys), (
'You have to provide all the commen keys!')
# write common keys
reformated = OrderedDict()
reformated["servarname"] = OrderedDict([
("index", dict_result['index']),
("host", dict_result['host'])
])
reformated["times"] = dict_result['_time']
reformated["metricTags"] = {"source": dict_result['source']}
# write metric
metric = None
for key in dict_result.keys():
if key not in common_keys:
metric = key
break
assert metric is not None, 'Cannot find metric in the OrderedDict!'
# don't know where you get this value. But you can customize it if needed
# for exampe if the metric name is needed here
reformated['metricName'] = "serverice count"
reformated['metricValue'] = dict_result[metric]
reformated['metricType'] = metric
return reformated
if __name__ == '__main__':
result= OrderedDict([('index', 'cfs_fsd_00001'),
('host', 'GIISSP707'),
('source', 'D:\\usrLLSS_SS'),
('_time', '2018-11-02 14:43:30.000 EDT'),
('count', '153')])
reformated = reformat_ordered_dict(result)
print(json.dumps(reformated))
</code></pre>