如何从Python中类似的字符串中获取值？

Question

假设我有以下字符串，来自包含类似字符串的文件：

Andorra la Vella|ad|Andorra la Vella|20430|42.51|1.51|
Canillo|ad|Canillo|3292|42.57|1.6|
Encamp|ad|Encamp|11224|42.54|1.57|
La Massana|ad|La Massana|7211|42.55|1.51|
...

如何使用正则表达式打印第一个数字（或每个字符串的第四个字段）？ 如果第4个数字超过10000，我如何打印特定行（例如“Andorr la Vella”“ad”“Andorr la Vella”20430）的前4个字段？你知道吗

Answer 1

你不需要正则表达式。你知道吗

s = """
Andorra la Vella|ad|Andorra la Vella|20430|42.51|1.51|
Canillo|ad|Canillo|3292|42.57|1.6|
Encamp|ad|Encamp|11224|42.54|1.57|
La Massana|ad|La Massana|7211|42.55|1.51|
"""

for line in s.splitlines():  # pretend we are reading from a file
    if not line:
        continue # skip empty lines

    groups = line.split('|')  # splits each line into its segments
    if int(groups[3]) > 10000:  # checks if the 4th value is above 10000
        print groups[:4]  # prints the first 4 values
    else:
        print groups[3]  # prints the 4th value

>>> 
['Andorra la Vella', 'ad', 'Andorra la Vella', '20430']
3292
['Encamp', 'ad', 'Encamp', '11224']
7211

Answer 2

我认为在这种情况下使用csv模块会更容易：

import csv
with open(filename, 'rb') as f:
    for row in csv.reader(f, delimiter='|'):
        num = float(row[3])
        if num > 10000:
            print(row[:4])

Answer 3

使用正则表达式：

import re
results = [re.match('(.*?\|)(.*?\|)(.*?\|)(.*?\|)(.*?\|)(.*?\|)', line).groups() for line in open('file.txt')]
# filter just the rows with fourth column > 10000
results = [result for result in results if int(result[3]) > 10000]

使用拆分：

results = [line.split('|')[0:-1] for line in open('file.txt')]
# filter just the rows with fourth column > 10000
results = [result for result in results if int(result[3]) > 10000]