我正在尝试在数学/科学/经济学页面下刮取所有可汗学院页面的标题和URL。然而,目前它只输出一个开放的括号,在这之前,它只会刮开始网址。你知道吗
from openbar_index.items import OpenBarIndexItem
from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
class OpenBarSpider(CrawlSpider):
"""
scrapes website URLs from educational websites and commits urls/webpage names/text to a document
"""
name = 'openbar'
allowed_domains = 'khanacademy.org'
start_urls = [
"https://www.khanacademy.org"
]
rules = [
Rule(SgmlLinkExtractor(allow = ['/math/']), callback='parse_item', follow = True),
Rule(SgmlLinkExtractor(allow = ['/science/']), callback='parse_item', follow=True),
Rule(SgmlLinkExtractor(allow = ['/economics-finance-domain/']), callback='parse_item', follow=True)
]
def parse_item(self, response):
item = OpenBarIndexItem()
url = response.url
item['url'] = url
item['title'] = response.xpath('/html/head/title/text()').extract()
yield item
有人知道为什么会发生这种情况,或者知道如何解决吗?你知道吗
问题是对
allowed_domains
的赋值。根据documentation,这不能是string
,而是list
。由于没有有效的域,因此使用该字符串,可能的结果将被scrapy过滤为异地请求。你知道吗所以在下一行加上方括号应该可以解决这个问题
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