重构python函数，使其可以接受任何大小的lis

Question

如何使此函数以任意列表大小作为输入？你知道吗

def ugly_function(lst):
    for a in lst[0]:
        for b in lst[1]:
            for c in lst[2]:
                for d in lst[3]:
                    for e in lst[4]:
                        for f in lst[5]:
                            for g in lst[6]:
                                for h in lst[7]:
                                    if some_test([a,b,c,d,e,f,g,h]): 
                                        return [a,b,c,d,e,f,g,h]

Answer 1

from itertools import ifilter, product

def nice_function(lst):
    return ifilter(some_test, product(*lst)).next()