我想当我点击其中一个可能的方块时,一个X被打印出来。 我已经列了一张tic-tac-toe网格的所有坐标表。我还添加了每个矩形坐标的中心点。如果我在X按钮显示的某个正方形区域内单击,我会尝试这样做。最终的目的是使双击结果成为一个结果。你知道吗
import matplotlib.pyplot as plt
import pygame
import sys
import pygame
pygame.font.init()
size = 320, 240
black = 0, 0, 0
white = 255,255,255
red = 255, 0, 0
x1y1 = [(100, 0), (100, 300)]
x2y2 = [(200, 0), (200, 300)]
x3y3 = [(0, 100), (300, 100)]
x4y4 = [(0, 200), (300, 200)]
def centroid(coord1, coord2):
xx = 50
yy = 50
coords = []
for a in range(0,3):
for b in range(0,3):
if a + 1 == int(coord1) and b + 1 == int(coord2):
coords += tuple([xx + a*100, yy + b*100])
return tuple(coords)
def fourCorners(a,b,length,width):
center = (a, b)
corner3 = (int(a + length/2), int(b + width/2))
corner2 = (int(a + length/2), int(b - width/2))
corner4 = (int(a - length/2), int(b + width/2))
corner1 = (int(a - length/2), int(b - width/2))
return [corner1 ,corner2 ,corner3 ,corner4]
def withinRect(a,b,corners):
if len(corners) != 4:
print('Pass a list parameter of length 4.')
elif int(corners[0][0]) >= int(a) >= int(corners[1][0]) and int(corners[0][1]) >= int(b) >= int(corners[1][1]):
return True
screen = pygame.display.set_mode((300,300))
screen.fill(white)
pygame.draw.line(screen, (0, 0, 255), x1y1[0], x1y1[1], 3)
pygame.draw.line(screen, (0, 0, 255), x2y2[0], x2y2[1], 3)
pygame.draw.line(screen, (0, 0, 255), x3y3[0], x3y3[1], 3)
pygame.draw.line(screen, (0, 0, 255), x4y4[0], x4y4[1], 3)
while True:
ev = pygame.event.get()
for event in ev:
# handle get_pressed
if event.type == pygame.MOUSEBUTTONUP:
pos = pygame.mouse.get_pos()
x, y = event.pos
v = fourCorners(centroid(1,1)[0],centroid(1,1)[1],100,100)
button = pygame.Rect(v[1][0], v[1][1] ,100,100)
if (withinRect(x,y,v) == True and button.collidepoint(event.pos)):
print('X')
pygame.display.flip()
else:
break
pygame.display.flip()
通过2个嵌套的LOO遍历所有9个字段,并为相应的字段定义一个^{} :
如果需要,可以定义边距,将区域限制在字段的中心:
使用^{} 检查单击是否在区域内:
从
bottomleft
到.topright
画一条线,从topleft
到.bottomright
画一条线,形成一个十字:相关问题 更多 >
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