与其他lis进行列表比较的列表

Question

我需要检查list with list是否包含与指定列表具有相似值的列表，值的顺序可能不同，但如果所有值都相同，则应返回true

a= ["1","2","3","4","5"]

b= ["2","3","6","4","7"]

e = (["1","3","2","4","5"],["2","3","6","4","7"])


CombinationFound = []
for i in e:
    if i == a:
        CombinationFound = True
        break;
    else:
        CombinationFound = False

它应该返回true，因为["1","2","3","4","5"]和["1","3","2","4","5"]具有相同的值

Answer 1

Pythonsets是针对特定问题的更好的实现。你知道吗

集合是包含数据的数学对象，但具有确定两个集合之间的并集、交集、差集等的方法。你知道吗

使用：

set(a) == set(b)

应该给你想要的结果。只要你说的“相似”是指“相同”。你知道吗

Answer 2

尝试将这些列表转换为集合：

def isthesame(a,b):
    return set(b) == set(a)

例如，如果您有：

a= ["1","2","3","4","5"]
b= ["2","3","6","4","7"]

此解决方案适用于没有重复项的列表。你知道吗

Answer 3

不使用for循环的不同比较方式：

found = any(set(a)==set(l) for l in e)