我有一个做递归的代码,但我想能够观察递归,但说明每个递归的深度,以及当它出来的时候。简单的如下所示。不知道我需要在哪里放置空格或制表符来实现这一点,我正在使用字符串映射\u str,然后在末尾打印出来。请参阅输出代码和示例。你知道吗
def get_process_parents(batchDate, late_process):
global late_parents
global map_str
process_depends = []
#logging.info('late_process: %s ' % late_process)
process_depends = getprocessDependencies(batchDate, late_process)
late_parents[late_process.get('name')] = process_depends
map_str += (' %s ---> %s \n------>\n' % (late_process.get('name'), process_depends))
#logging.info('Late_process Name: %s ---> Depends: %s ' % (late_process.get('name'),process_depends))
if not process_depends:
#logging.info('No more depends: %s' % late_process.get('name'))
late_parents_process.add(late_process.get('name'))
map_str += (' %s ---> %s\n ---->\n' % (late_process.get('name'), process_depends))
else:
for process_depend in process_depends:
process = getprocessByName(batchDate, process_depend)
#logging.info('process_depend %s --> state: %s ' % (process_depend, process.get('state')))
if process.get('state') == 'Done':
#logging.info('process depend DONE: %s' % process_depend)
map_str += (' %s Status: %s\n ---->\n' % (process_depend, process.get('state')))
else:
late_parents_process.add(process.get('name'))
get_process_parents(batchDate, getprocessByName(batchDate,process_depend))
输出:
我想要的样子
Process_name ----> ['process dependencies 1', 'process dependencies 2']
------>process dependencies 1 ----> [process dependencies 3, dependencies 4]
------>dependencies 3 -----> []
------>dependencies 4 -----> []
------>process dependencies 2 ----> [process dependencies 5]
------>process dependencies 5 -----> [process dependencies 6]
----->process dependencies 6 -----> []
你能改变函数签名吗?如果是这样,那么最简单的方法就是将函数定义为:
然后在嵌套调用中使用
然后,要缩进,可以使用:
如果你能避免的话,我会提醒你不要使用全局映射。你知道吗
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