inputfile=open('inputfile.txt', 'r')
cleaned_resume= inputfile.read()
def fetch_skills(cleaned_resume):
with open('skillsdata.csv', 'r') as skills:
skill_set=[]
for skill in skills:
if skill in cleaned_resume:
print(skill)
skill_set.append(skill)
return skill_set
if __name__ == '__main__':
skills = fetch_skills(cleaned_resume)
print(skills)
在skillsdata中匹配后,我想从“干净的简历”中提取技能。但它给出了错误的输出。你知道吗
尝试运行以下命令:
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