解码/编码链接

Question

如何获得expected的结果以返回可读字符串？换句话说，当给定/wiki/Cookbook:Cao_l%E1%BA%A7u时，它应该返回/wiki/Cookbook:Cao_lầu。你知道吗

注意：我运行的是Python2.7.2

import urllib

test_array = [
    '/wiki/Cookbook:Bulgarian_Meatball_Soup_(Supa_Topcheta)',
    '/wiki/Cookbook:Campfire_S%27mores',
    '/wiki/Cookbook:Candied_Almonds_(Br%C3%A4nda_mandlar)',
    '/wiki/Cookbook:Chicken_%26_Pasta_Alfredo',   
    '/wiki/Cookbook:Cozido_%C3%A0_Portuguesa'
]

actual = [urllib.unquote(i).decode('utf-8') for i in test_array]

assert '/wiki/Cookbook:Bulgarian_Meatball_Soup_(Supa_Topcheta)' == actual[0]
assert "/wiki/Cookbook:Campfire_S'mores" == expected[1]
assert '/wiki/Cookbook:Candied_Almonds_(Brända_mandlar)' == actual[2]
assert '/wiki/Cookbook:Chicken_&_Pasta_Alfredo' == actual[3]
assert '/wiki/Cookbook:Cozido_à_Portuguesa' == actual[4]

Answer 1

您需要指定unicode文本（前缀为u）而不是字符串文本，因为^{}返回unicode对象。你知道吗

assert u'/wiki/Cookbook:Bulgarian_Meatball_Soup_(Supa_Topcheta)' == expected[0]
assert u"/wiki/Cookbook:Campfire_S'mores" == expected[1]
assert u'/wiki/Cookbook:Candied_Almonds_(Brända_mandlar)' == expected[2]
assert u'/wiki/Cookbook:Chicken_&_Pasta_Alfredo' == expected[3]
assert u'/wiki/Cookbook:Cozido_à_Portuguesa' == expected[4]

顺便说一句，我会给expected一个不同的名字，比如actual或got。（字符串文字是预期的结果，对吗？）你知道吗