如何在不重复代码的情况下打开多个文件

Question

我正在做一个程序，将打开多个文件，他们都非常相似。在记事本上包含几个小写的单字行。我不想重复代码多次。理想情况下，我希望使用while循环来重复代码，但每次重复时都要更改它打开的文件。有办法吗？ 这是当前代码：

File = open("Key Words\Audio.txt","r") #This will open the file called Audio.
Audio = [] #This creates the Audio list
Audio = File.read().splitlines() #This saves everything on each line of the  Audio file to a diffrent section of the Audio list.


File = open("Key Words\Calls.txt","r") #This will open the file called Calls.
Calls = [] #This creates the Calls list
Calls = File.read().splitlines() #This saves everything on each line of the Calls file to a diffrent section of the Calls list.


File = open("Key Words\Charging.txt","r") #This will open the file called Charging.
Charging = [] #This creates the Charging list
Charging = File.read().splitlines() #This saves everything on each line of the Charging file to a diffrent section of the Charging list.

File.close() #This closes the File(s).

Answer 1

列出需要打开的文件：

files_to_open = [
    'file_1.txt',
    'file_2.txt'
]

calls_info = {}

迭代列表，打开并处理：

for file_ in files_to_open:
    with open(file_) as f:
        calls_info[file_] = f.read().splitlines()

在这里，我创建了一个calls_info变量。这样做就是把所有的东西都存储在字典里。它们包含键和值—要访问文件的值，只需按如下方式对其进行索引：

calls_info[file_path] # Make sure file_path is the right path you put in the list!