擅长:python、mysql、java
<p>我建议先指定当前时间数据的格式</p>
<pre><code>df['time_exit'] = pd.to_datetime(df['time_exit'] , errors='coerce', format='%d/%m/%Y %H:%M:%S', infer_datetime_format=True)
df['time_entry'] = pd.to_datetime(df['time_entry'] , errors='coerce', format='%d/%m/%Y %H:%M:%S', infer_datetime_format=True)
</code></pre>
<p>在这之后:</p>
<pre><code>df[['tempo']] = df['time_exit'] - df['time_entry']
</code></pre>
<p>如果您只需要天数差异:</p>
<pre><code>df[['tempo']] = (df['time_exit'] - df['time_entry']).dt.days
</code></pre>