<p>一个<strong>python3.5</strong>解决方案,展示了新的dict<em>解包</em>。你知道吗</p>
<pre><code>[{**dict_element, **{u'client_id':u'12398'}} for dict_element in your_list]
</code></pre>
<p>检查<a href="https://www.python.org/dev/peps/pep-0448/" rel="nofollow">this</a>。你知道吗</p>
<p>演示</p>
<pre><code>>>> your_list = [{u'ID': 46757,
... u'currentenddate': u'09/30/2016',
... u'name': u'Project A',
... u'projstartdate': u'05/01/2016'},
... {u'ID': 46625,
... u'currentenddate': u'07/15/2016',
... u'name': u'Project B',
... u'projstartdate': u'05/02/2016'},
... {u'ID': 47100,
... u'currentenddate': u'08/02/2016',
... u'name': u'Project C',
... u'projstartdate': u'06/01/2016'}]
>>>
>>> from pprint import pprint
>>> pprint([{**dict_element, **{u'client_id':u'12398'}} for dict_element in your_list])
[{'ID': 46757,
'client_id': '12398',
'currentenddate': '09/30/2016',
'name': 'Project A',
'projstartdate': '05/01/2016'},
{'ID': 46625,
'client_id': '12398',
'currentenddate': '07/15/2016',
'name': 'Project B',
'projstartdate': '05/02/2016'},
{'ID': 47100,
'client_id': '12398',
'currentenddate': '08/02/2016',
'name': 'Project C',
'projstartdate': '06/01/2016'}]
</code></pre>