擅长:python、mysql、java
<p>使用Python的另一种解决方案是:</p>
<pre><code>ints = [1, 2, 3, 4, 5, 6, 7, 8]
print sum(y - x for x, y in zip(*([iter(ints)] * 2)))
ints = [4, 8, 8, 3, 9, 0, 7, 8, 2, 2]
print sum(y - x for x, y in zip(*([iter(ints)] * 2)))
</code></pre>
<p>给予:</p>
<pre><code>4
-9
</code></pre>