在Pandas中，如何检查三个组合字符串列是否==10个字符，如果是，则插入到新列中？

Question

我想把三个字符串列合并成一个新列，如果新列的组合字符总数等于10。你知道吗

如果不等于10，则检查下一个组合列。你知道吗

如果Phone1Area等于3个字符串字符，Phone1Prefix等于3个字符串字符，Phone1NumberPart等于4个字符串字符，换句话说，总共10个字符，我尝试将这些列添加到一个新列中。我试过添加3+3+4个字符的列，测向位置，还有更多的事情。你知道吗

以下是数据集示例：

代码如下：

dfp['p1'] = df[(df['Phone1Area'].str.len() == 3.0)]['Phone1Area'] + 
df[(df['Phone1Exchange'].str.len() == 3.0)]['Phone1Exchange'] + 
df[(df['Phone1NumberPart'].str.len() == 4.0)]['Phone1NumberPart']


dfp['p2'] = df[(df['Phone2Area'].str.len() == 3.0)]['Phone2Area'] + 
df[(df['Phone2Exchange'].str.len() == 3.0)]['Phone2Exchange'] + 
df[(df['Phone2NumberPart'].str.len() == 4.0)]['Phone2NumberPart']

df_phone.loc[df_phone['p1'].str.len() == 10, 'phone'] = df_phone['p1']
df_phone.loc[df_phone['p2'].str.len() == 10, 'phone'] = df_phone['p2']

以下是我想要它做的，但是在熊猫身上：

if df_phone['p1'].str.len() == 10:
    then insert df_phone['p1'] into df_phone['phone']
elif df_phone['p2'].str.len() == 10:
    then insert df_phone['p2'] into df_phone['phone']
elif df_phone['p3'].str.len() == 10:
    then insert df_phone['p3'] into df_phone['phone']

我希望phone列包含phone1的10个字符，如果不是10个字符，那么phone列包含phone2的10个字符，以此类推

但其中一个结果是：

AttributeError: 'DataFrame' object has no attribute 'str'

你知道怎么解决吗？你知道吗

Answer 1

这将有助于：

df['phone'] = ''
df['test_phone'] = df['phone1Area'] + df['phone1Exchange'] + df['phone1NumberPart']
df['phone'][df['test_phone'].str.len() == 10] = df['test_phone']
df['test_phone'] = df['phone2Area'] + df['phone2Exchange'] + df['phone2NumberPart']
df['phone'][(df['test_phone'].str.len() == 10) & (df['phone'] == '')] = df['test_phone']
df['test_phone'] = df['phone3Area'] + df['phone3Exchange'] + df['phone3NumberPart']
df['phone'][(df['test_phone'].str.len() == 10) & (df['phone'] == '')] = df['test_phone']
etc.