擅长:python、mysql、java
<p>就像十二生肖提到的,如果没有一个直接的问题,很难回答;但是,我会尝试一个解决方案。你知道吗</p>
<pre><code>#Merge Lists of Dictionaries Functions
def merge_lists(l1, l2, key):
merged = {}
for item in l1+l2:
if item[key] not in merged:
merged[item[key]] = item
return [val for (_, val) in merged.items()]
</code></pre>
<p>告诉我这是怎么回事</p>