擅长:python、mysql、java
<p>另一种方法是在<code>for-loop</code>内部检查<code>i</code>是奇数还是偶数。只是围绕着Shobhit Verma的答案。你知道吗</p>
<pre><code>num_page_items = len(odds)
for i in range(num_page_items):
if i % 2 == 0: #This is a sanity check to see if i is odd or even
Home = odds[i].text
else:
Away = odds[i].text
</code></pre>