<p>这个怎么样。它可以得到您想要的输出,但是树结构可能更干净。你知道吗</p>
<pre><code>from collections import defaultdict
import json
def nested_dict():
"""
Creates a default dictionary where each value is an other default dictionary.
"""
return defaultdict(nested_dict)
def default_to_regular(d):
"""
Converts defaultdicts of defaultdicts to dict of dicts.
"""
if isinstance(d, defaultdict):
d = {k: default_to_regular(v) for k, v in d.items()}
return d
def get_path_dict(paths):
new_path_dict = nested_dict()
for path in paths:
parts = path.split('/')
if parts:
marcher = new_path_dict
for key in parts[:-1]:
marcher = marcher[key]
marcher[parts[-1]] = parts[-1]
return default_to_regular(new_path_dict)
l1 = ['foo/e.txt','foo/bar/a.txt','foo/bar/b.cfg','foo/bar/c/d.txt', 'test.txt']
result = get_path_dict(l1)
print(json.dumps(result, indent=2))
</code></pre>
<p>输出:</p>
<pre><code>{
"foo": {
"e.txt": "e.txt",
"bar": {
"a.txt": "a.txt",
"b.cfg": "b.cfg",
"c": {
"d.txt": "d.txt"
}
}
},
"test.txt": "test.txt"
}
</code></pre>