擅长:python、mysql、java
<p>下面是与OP中的确切需求相匹配的xpath</p>
<pre><code>//span[normalize-space(.)='Article 1.']/ancestor::p|//p[//span[normalize-space(.)='Article 1.']]/following::*[count(following-sibling::p/span/b[normalize-space(.)='PRIME MINISTER'])=1]
</code></pre>
<p>截图:</p>
<p><a href="https://i.stack.imgur.com/b1kEx.gif" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/b1kEx.gif" alt="date"/></a></p>