如何从网站获取请求?我发现这个: http://www.yodaspeak.co.uk/webservice/yodatalk.php?wsdl
但我可以想出如何向它发送请求并得到响应。你知道吗
到目前为止,我试过:
import requests
yoda_params = {"inputText": 'Is this working?'}
yoda_url = 'http://www.yodaspeak.co.uk/webservice/yodatalk.php?'
yoda_re = requests.get(yoda_url, params=yoda_params)
yoda_text = yoda_re.json()
print(yoda_text)
但没用。你知道吗
Name: yodaTalk
Binding: http://www.yodaspeak.co.uk/webservice/yodatalkBinding
Endpoint: http://www.yodaspeak.co.uk/webservice/yodatalk.php
SoapAction: uri:http://www.yodaspeak.co.uk/webservice/yodatalk#yodaTalk
Style: rpc
Input:
use: literal
namespace: uri:http://www.yodaspeak.co.uk/webservice/yodatalk
encodingStyle:
message: yodaTalkRequest
parts:
inputText: xsd:string
Output:
use: literal
namespace: uri:http://www.yodaspeak.co.uk/webservice/yodatalk
encodingStyle:
message: yodaTalkResponse
parts:
return: xsd:string
Namespace: uri:http://www.yodaspeak.co.uk/webservice/yodatalk
Transport: http://schemas.xmlsoap.org/soap/http
Documentation: Pass any string and it will be returned as Yoda-Speak.
我在尝试将InputText=Something放入url时也发现了这个错误
更新:
我尝试了zeep,但是当我运行python -mzeep 'http://www.yodaspeak.co.uk/webservice/yodatalk.php?wsdl
时,我得到:
No namespace defined for 'http' ('http://www.yodaspeak.co.uk/webservice/yodatalkPortType')
尝试使用任何soap库(例如,zeep)。 在
http://www.yodaspeak.co.uk/webservice/yodatalk.php?wsdl
中有wsdl
,所以我想是关于soap
使用的。你知道吗相关问题 更多 >
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