空间数组枚举上标量变量的索引无效

Question

我试图在本地运行以下句子压缩：https://github.com/zhaohengyang/Generate-Parallel-Data-for-Sentence-Compression

所以我复制了文件并用conda安装了所有的依赖项。我做了一些小的修改，比如从url读取数据，而不是从本地磁盘读取数据，并放置了他的并行数据_py代捆绑在我的单个py文件中。你知道吗

但是当我运行它时，我得到：

空间库无法将句子解析到树中。请忽略这对句子

----------------59-------------------
reducing sentence: This year the Venezuelan government plans to continue its pace of land expropriations in order to move towards what it terms ``agrarian socialism''.
reducing headline: Venezuelan government to continue pace of land expropriations for ``agrarian socialism''
Traceback (most recent call last):
  File "/home/user/dev/projects/python-snippets/zhaohengyang/sentence-compression.py", line 701, in <module>
    reduce_sentence(sample)
  File "/home/user/dev/projects/python-snippets/zhaohengyang/sentence-compression.py", line 641, in reduce_sentence
    sentence_info = parse_info(sentence)
  File "/home/user/dev/projects/python-snippets/zhaohengyang/sentence-compression.py", line 616, in parse_info
    heads = [index + item[0] for index, item in enumerate(doc.to_array([HEAD]))]
IndexError: invalid index to scalar variable.

我不知道如何解决这个问题，因为我是一个相当新的python用户。你知道吗

下面是我用来重现问题的完整代码：https://gist.github.com/avidanyum/3edfbc96ea22807445ab5307830d41db

失败的内部代码段：

def parse_info(sentence):
    doc = nlp(sentence)

    heads = [index + item[0] for index, item in enumerate(doc.to_array([HEAD]))]

现在我加载了nlp：

import spacy
print('if you didnt run: python -m spacy download en')
import spacy.lang.en
nlp = spacy.load('en')

有关我的环境的更多信息：

/home/user/home/user/dev/anaconda3/envs/pymachine/bin/python --version
Python 2.7.15 :: Anaconda, Inc.

Answer 1

请注意，我正在Python3.6上运行Spacy2.0，但只是在一个示例语句上运行了一个快速测试：

nlp = spacy.load('en_core_web_lg')

doc = nlp("Here is a test sentence for me to use.")

我在运行您的代码时遇到一些错误，这两个错误都在您指定的行中：

heads = [(index, item) for index, item in enumerate(doc.to_array([HEAD]))]
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name 'HEAD' is not defined

这是因为to_array调用接受list个string对象。将其修复为：

# Note that HEAD is now a string, rather than a variable
heads = [(index, item) for index, item in enumerate(doc.to_array(['HEAD']))]
heads
[(0, 3), (1, 1), (2, 1), (3, 0), (4, 18446744073709551615), (5, 1), (6, 18446744073709551614), (7, 18446744073709551612)]

解决问题。您还将注意到，enumerate返回的item是int或scalar类型，因此它没有索引属性。摆脱你的index[0]这会解决你的问题。你知道吗

没有错误的方法：

def parse_info(sentence):
    doc = nlp(sentence)

    heads = [index + item for index, item in enumerate(doc.to_array(['HEAD']))]