如果x比y高3个单位

Question

我正在做一个程序来做一个猜谜游戏；我需要能够让程序给出H或L的反馈，只有当一个数字比随机数高3或低3的时候。你知道吗

这就是我现在拥有的

import random
def game3():
    rndnumber = str(random.randint(0,9999)) #gets a number between 0-9999
    while len(rndnumber) < 4: 
        rndnumber = '0'+ rndnumber # adds 0s incase the number is less then a 1000
    print(rndnumber) #lets me know that the program generates the right type of number (remove this after testing)
    feedback = 0 #adds a variable
    for x in range(1,11): #makes a loop that runs for 10 times
        print("Attempt",x)
        attempt = input("Guess a number between 0-9999:")#gets the users guess
        feedback = "" #makes a feedback variable
        for y in range(4): #makes a loop that runs for 4 times
            if attempt[y] == rndnumber[y]: #if attempt is the same then add a Y to the number
                feedback += "Y"
            elif attempt[y] < rndnumber[y]:
                feedback += "L"
            elif attempt[y] > rndnumber[y]:
                feedback += "H"
            else:
                feedback += "N"
        print(feedback)
        if  x == 10:
            print("You Lose the correct answer was",rndnumber)
        if feedback == "YYYY" and x > 1:
            print("You win it took",x,"attempts.")
            break; #stops the program
        elif feedback == "YYYY":
            print("You won on your first attempt!")
            break; #stops the program

Answer 1

If x is 3 higher than y

if x+3 == y:
    #code

the program give feedback only if a number is 3 higher than the random number or 3 less.

if x+3 == y or x-3 == y:
    #give feedback

资料来源：

http://anh.cs.luc.edu/python/hands-on/3.1/handsonHtml/ifstatements.html

Answer 2

在第10行中，您在变量尝试中保存了一个字符串。 然而，在第13行中，您将尝试用作字典。你知道吗

你可能想重新考虑一下你的整个方法。你知道吗

编辑：

当然，我也曾经做过一个猜谜游戏。虽然我现在肯定会使用一种不同的方法，但我认为它可能会对您有所帮助，并在python3代码中为您自己的游戏构建需求。你知道吗

import random

print ("Hello! What is your name?")
name = input()
print ("Well,", name, ", I am thinking of a number between 1 and 100.\nTake a guess.")
number = random.randint(1, 100) # create a number between 1 and 100
guess = input() # read user's guess
guess = int(guess)
guessnumber = 1 # first try to guess the number
guessed = False # number isn't guessed yet
while guessed == False:
    if (number == guess):
        print ("Good job,", name + "! You guessed my number in",guessnumber, "guesses!")
        guessed = True
    elif (guess > number):
        print ("Your guess is too high.")
        guess = input("Take another guess: ")
        guess = int(guess)
        guessnumber+=1
    else:
        print ("Your guess is too low.")
        guess = input("Take another guess: ")
        guess = int(guess)
        guessnumber+=1

Answer 3

你可以用

if attempt == rndnumber + 3 or attempt == rndnumber - 3:
    # Do something...