函数和if/elif语句总是首先返回if语句

Question

好的，我正在尝试创建一个程序，这个程序需要三个DNA碱基，然后给你免费的氨基酸。我能有效地将DNA转录成互补的RNA，但我的翻译功能不起作用。你知道吗

Here is my code: 
def basematch(base):
if base == "A":
    return "U"
elif base == "T":
    return "A"
elif base == "G":
    return "C"
elif base == "C":
    return "G"
else:
    return "invalid"




rawdna = raw_input("Enter a raw DNA sequence: ")
comp = list(rawdna)
length = len(comp)

n = 0


codonlist = []


while n + 1 <= length:
    final = comp[n]
    finalbase = basematch(final)
    codonlist.append(finalbase)
    n = n + 1


rawRNA = "".join(codonlist)

def translate(codon):
    if codon == "GCU" or "GCC" or "GCA" or "GCG":
       print 'Ala'
    elif codon == "UUU" or "UUC":
       print "Phe"
    elif codon == "UUA" or "UUG":
       print "Leu" 
    elif codon == "UGU" or "UGC": 
       print "Cys"
    elif codon == "UGA" or "UAA" or "UAG": 
       print "Stop"
    elif codon == "UGG" or "UAU" or "UAC": 
       print "Tyr"
    elif codon == "UCU" or "UCC" or "UCA" or "UCG":
       print "Ser"
    elif codon == "CUU" or "CUC" or "CUA" or "CUG":
       print "Leu"
    elif codon == "CCU" or "CCC" or "CCA" or "CCG":
       print "Pro"
    elif codon == "CAU" or "CAC":
       print "His"
    elif codon == "CAA" or "CAG":
       print "Gln"
    elif codon == "CGU" or "CGC" or "CGA" or "CGG":
       print "Arg"

translate(rawRNA) 

每当我翻译rawRNA时，它总是返回“Ala”。你知道吗

抱歉，代码太长了。谢谢你的帮助。你知道吗

Answer 1

线路没有检查好。你知道吗

if codon == "GCU" or "GCC" or "GCA" or "GCG":

or并没有扩展到==；它将检查if "GCC":，它总是True，因此它结束于此。你知道吗