长度为X>长度为Y的旋转串

Question

变量x和y中有两个字符串，其中x的长度大于y的长度。如何将较小的字符串（y）映射到较大的字符串（x）的大小？你知道吗

例如：

x = "appleappleapple" # (length 15)
y = "abc" # (length 3) This should be mapped to "abcabcabcabcabc"

while len(y) < len(x):
    y+=y
while len(y) > len(x):
    y = y[:-1] 

print x 
print y 

appleappleapple
abcabcabcabcabc

有没有一种非常有效的方法来做这个手术？你知道吗

Answer 1

x = "appleappleapple" # (length 15)
y = "abc" # (length 3) This should be mapped to "abcabcabcabcabc"
z = (y*(len(x)/len(y)+1))[:len(x)]