寻找一个词接一个词的方法，Python

Question

如何创建一个函数来获取“class”后面的单词，只要它不是引号（单引号、双引号或任何三引号）并且拼写正确（不能获取class d（）

"class hi()"  > hi

"class hi(dff)"  > hi

"class hi   (  dff  )  :"  > hi 

"  class        hi       (  dff  )  :"  > hi 

"class hi"  > hi

"classf hi"  > Nothing

"fclass hi"  > Nothing

"'class hi(dd)'"  > Nothing

'"class hi(dd)"'  > Nothing

"'''class hi(dd)'''"  > Nothing

'"""class hi(dd)"""'  > Nothing

'"""\n\n\n\nclass hi(dd)\n\n\n\n"""'  > Nothing    

"'class' hi()"  > Nothing

使用循环创建太难了。如果有人能帮忙那就太好了，谢谢。这很有挑战性

Answer 1

也许是这样的？你知道吗

from StringIO import StringIO
from tokenize import generate_tokens
from token import NAME

def classname(s):
    g = generate_tokens(StringIO(s).readline)   # tokenize the string
    it = iter(g)
    for toknum, tokval, _, _, _  in it:
        if (toknum == NAME and tokval == 'class'):
            return it.next()[1]

print classname("class hi(29):")