如何将字典中的值提取到数组中

Question

spades = ['2S','3S','4S','5S','6S','7S','8S','9S','10S','JS','QS','KS','AS']
hearts = ['2H','3H','4H','5H','6H','7H','8H','9H','10H','JH','QH','KH','AH']
clubs = ['2C','3C','4C','5C','6C','7C','8C','9C','10C','JC','QC','KC','AC']
diamonds = ['2D','3D','4D','5D','6D','7D','8D','9D','10D','JD','QD','KD','AD']
allCards = spades + hearts + clubs + diamonds

import random
random.shuffle(allCards)

bot1 = [allCards.pop() for i in range(2)]
print(bot1)
cardVal = {'2S':1,'3S':2,'4S':3,'5S': 4,'6S':5,'7S':6,'8S':7,'9S':8,'10S':9,'JS':10,'QS':11,'KS':12,'AS':13,
    '2H':1,'3H':2,'4H':3,'5H': 4,'6H':5,'7H':6,'8H':7,'9H':8,'10H':9,'JH':10,'QH':11,'KH':12,'AH':13,
    '2C':1,'3C':2,'4C':3,'5C': 4,'6C':5,'7C':6,'8C':7,'9C':8,'10C':9,'JC':10,'QC':11,'KC':12,'AC':13,
    '2D':1,'3D':2,'4D':3,'5D': 4,'6D':5,'7D':6,'8D':7,'9D':8,'10D':9,'JD':10,'QD':11,'KD':12,'AD':13}

for i in bot1:
    print(cardVal[i])
    bot1hand = [cardVal[i]]
print(bot1hand)

我想把bot1拥有的卡的值放在一个单独的数组中，但是遇到了问题。我总是将这两个值打印在不同的行上，数组bot1hand只存储这两个值中的最后一个。你知道吗

例如：

>>> 
['AC', '5C']
13
4
[4]
>>> 

Answer 1

你的for循环就是问题所在。您可能需要尝试列表comprehension：

bot1hand = [cardVal[i] for i in bot1]
print(bot1hand)

（我假设print语句用于调试目的。）

列表理解负责为您实际构建列表。你知道吗

Answer 2

你的问题就在这里：

for i in bot1:
    print(cardVal[i])
    bot1hand = [cardVal[i]]
print(bot1hand)

尤其是这一行：

bot1hand = [cardVal[i]]

你一直在写你的价值观，因为你实际上没有正确地附加到你的清单上。事实上，你的手并不是一张单子。你知道吗

首先要将其初始化为循环外的列表：

bot1hand = []

然后在循环中，对其使用append方法：

bot1hand.append(cardVal[i])

所以最后一段代码应该是这样的：

bot1hand = []
for i in bot1:
    print(cardVal[i])
    bot1hand.append(cardVal[i])
print(bot1hand)

作为代码中的最后一个重构步骤，您实际上可以按照@NathanielFord的建议，使用理解（我看到您已经在代码中使用了理解，所以您必须已经熟悉它）。我在这个答案中的那部分代码现在可以简化为：

bot1hand = [cardVal[i] for i in bot1]