擅长:python、mysql、java
<p>您可以使用<code>collections.Counter</code>稍微简化一下:</p>
<pre><code>summed_dict = collections.Counter()
for d in partial_dicts:
summed_dict.update(d)
# Use .viewitems or .iteritems instead of .items on Py2
average_dict = {k: v / len(partial_dicts) for k, v in summed_dict.items()}
</code></pre>