擅长:python、mysql、java
<p>来,试试这个,手工制作的:)</p>
<pre><code>for i, _ in enumerate(s): #i here is the index, equal to "i in range(len(s))"
if s[i:i+3] == 'bob': #Check the current char + the next three chars.
bob += 1
print('Number of times bob occurs is: ' + str(bob))
</code></pre>
<p><strong>演示</strong></p>
<pre><code>>>> s = 'gfdhbobobyui'
>>> bob = 0
>>> for i, v in enumerate(s): #i here is the index, equal to "i range(len(s))"
if s[i:i+3] == 'bob': #Check the current char + the next two chars.
bob += 1
>>> bob
2
</code></pre>
<p>希望这有帮助!</p>